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comparing the `prototype` property isn't useful #6

timbertson opened this Issue Apr 15, 2013 · 1 comment


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I assumed from reading the code that the following test case should pass:

test('differing types', function (t) {
    t.notOk(equal(["a","b"], {0: "a", 1: "b"}));

It doesn't (i.e it considers those objects equal), since prototype is generally undefined unless you're comparing constructor functions. I think you mean:

    if (Object.getPrototypeOf(actual) !== Object.getPrototypeOf(expected)) return false;

(or some equivalent where that function is not available)


substack commented Apr 15, 2013

I didn't write this code, I copied it from node's assert library. The only bugs I'm willing to accept fixes for are where this library deviates from node core but this is how it works in node core too:

$ node
> require('assert').deepEqual(["a","b"], {0: "a", 1: "b"})

@substack substack closed this Apr 15, 2013

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