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|
| Previous ID |
SR-7266 |
| Radar |
None |
| Original Reporter |
@moiseev |
| Type |
Improvement |
| Status |
Resolved |
| Resolution |
Done |
Additional Detail from JIRA
|
|
| Votes |
0 |
| Component/s |
Standard Library |
| Labels |
Improvement, StarterBug |
| Assignee |
@Moximillian |
| Priority |
Medium |
md5: d7a13ecbc1a535d769141383adecf60a
Issue Description:
Right now applying reversed() twice will result in a ReversedCollection<ReversedCollection<Base>>.
(swift) [1,2].lazy.reversed()
// r0 : LazyCollection<ReversedCollection<[Int]>> = Swift.LazyCollection<Swift.ReversedCollection<Swift.Array<Swift.Int>>>(_base: Swift.ReversedCollection<Swift.Array<Swift.Int>>(_base: [1, 2]))
(swift) r0.reversed()
// r1 : LazyCollection<ReversedCollection<ReversedCollection<[Int]>>> = Swift.LazyCollection<Swift.ReversedCollection<Swift.ReversedCollection<Swift.Array<Swift.Int>>>>(_base: Swift.ReversedCollection<Swift.ReversedCollection<Swift.Array<Swift.Int>>>(_base: Swift.ReversedCollection<Swift.Array<Swift.Int>>(_base: [1, 2])))
(swift) [1].reversed()
// r2 : ReversedCollection<[Int]> = Swift.ReversedCollection<Swift.Array<Swift.Int>>(_base: [1])
(swift) r2.reversed()
// r3 : ReversedCollection<ReversedCollection<[Int]>> = Swift.ReversedCollection<Swift.ReversedCollection<Swift.Array<Swift.Int>>>(_base: Swift.ReversedCollection<Swift.Array<Swift.Int>>(_base: [1]))
I believe we can be smarter and avoid this nesting.
Additional Detail from JIRA
md5: d7a13ecbc1a535d769141383adecf60a
Issue Description:
Right now applying
reversed()twice will result in a ReversedCollection<ReversedCollection<Base>>.I believe we can be smarter and avoid this nesting.