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Quick examples
This page provides quick examples of common symbolic calculations in SymPy. You can print it and keep it handy for reference.
Take a look at the introductory tutorial as well. introductory tutorial.
>>> from sympy import *
>>> x, y, z, t = symbols('x y z t')
>>> k, m, n = symbols('k m n', integer=True)
>>> f, g, h = symbols('f g h', cls=Function)Construct the formula
>>> Rational(3,2)*pi + exp(I*x) / (x**2 + y)
3*pi/2 + exp(I*x)/(x**2 + y)Calculate the value of
>>> x = Symbol('x')
>>> exp(I*x).subs(x,pi).evalf() #doctest: +SKIP
-1.00000000000000 >>> expr = x + 2*y
>>> expr.__class__
<class 'sympy.core.add.Add'>
>>> expr.args
(2*y, x)Calculate 50 digits of
>>> exp(pi * sqrt(163)).evalf(50)
262537412640768743.99999999999925007259719818568888Suppressing evaluation :
>>> latex(S('2*4+10',evaluate=False))
'2 \\cdot 4 + 10'Allowing evaluation
>>> latex(exp(x*2)/2)
'\\frac{e^{2 x}}{2}'Expand
>>> ((x+y)**2 * (x+1)).expand()
x**3 + 2*x**2*y + x**2 + x*y**2 + 2*x*y + y**2Simplify
>>> a = 1/x + (x*sin(x) - 1)/x
>>> simplify(a)
sin(x)Find the roots of
>>> solve(Eq(x**3 + 2*x**2 + 4*x + 8, 0), x)
[-2*I, 2*I, -2]or more easily:
>>> solve(x**3 + 2*x**2 + 4*x + 8, x)
[-2*I, 2*I, -2]For details, see: Finding roots of polynomials.
Solve the equation system
>>> solve([Eq(x + 5*y, 2), Eq(-3*x + 6*y, 15)], [x, y])
{x: -3, y: 1}or
>>> solve([x + 5*y - 2, -3*x + 6*y - 15], [x, y])
{x: -3, y: 1}Solve
>>> y=Function('y')
>>> n=Symbol('n', integer=True)
>>> f=y(n)-2*y(n-1)-5*y(n-2)
>>> rsolve(f,y(n),[1,4])
(1/2 - sqrt(6)/4)*(1 - sqrt(6))**n + (1/2 + sqrt(6)/4)*(1 + sqrt(6))**nEvaluate
>>> a, b = symbols('a b')
>>> s = Sum(6*n**2 + 2**n, (n, a, b))
>>> s
Sum(2**n + 6*n**2, (n, a, b))
>>> s.doit()
-2**a + 2**(b + 1) - 2*a**3 + 3*a**2 - a + 2*b**3 + 3*b**2 + bEvaluate
>>> product(n*(n+1), (n, 1, b))
RisingFactorial(2, b)*b!Example: if
>>> f=Function('f')
>>> ex=Eq(f(1/x)-3*f(x),x)
>>> ex.subs(x,2)
f(1/2) - 3*f(2) == 2
>>> ex.subs(x,Rational(1,2))
-3*f(1/2) + f(2) == 1/2
>>> solve([f(Rational(1,2))-3*f(2)-2,-3*f(Rational(1,2))+f(2)-Rational(1,2)])
[{f(2): -13/16, f(1/2): -7/16}]Evaluate
>>> limit((sin(x)-x)/x**3, x, 0)
-1/6Find the Maclaurin series of
>>> (1/cos(x)).series(x, 0, 6)
1 + x**2/2 + 5*x**4/24 + O(x**6)Differentiate
>>> diff(cos(x**2)**2 / (1+x), x)
-4*x*sin(x**2)*cos(x**2)/(x + 1) - cos(x**2)**2/(x + 1)**2Calculate the indefinite integral
>>> integrate(x**2 * cos(x), x)
x**2*sin(x) + 2*x*cos(x) - 2*sin(x)Calculate the definite integral
>>> integrate(x**2 * cos(x), (x, 0, pi/2))
-2 + pi**2/4Solve
>>> f = Function('f')
>>> dsolve(Eq(Derivative(f(x),x,x) + 9*f(x), 1), f(x))
f(x) == C1*cos(3*x) + C2*sin(3*x) + 1/9You can also use .diff(), like here (an example in isympy)
>>> f = Function("f")
>>> Eq(f(x).diff(x, x) + 9*f(x), 1)
9*f(x) + Derivative(f(x), x, x) == 1
>>> dsolve(_, f(x))
f(x) == C1*cos(3*x) + C2*sin(3*x) + 1/9