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Square One +2 second penalty #130

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jfly opened this issue Dec 28, 2013 · 5 comments

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@jfly
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commented Dec 28, 2013

Take a solved sq1. Apply the move (6, 6) to it. This puzzle is exactly 1 move away from solved, as per https://www.worldcubeassociation.org/regulations/2014-draft/#12c. By https://www.worldcubeassociation.org/regulations/2014-draft/#10e3, that means that this puzzle is solved with a 2 second penalty.

I asked Lucas about this, and he confirmed that this is a correct interpretation of the regs, but not intended, as it is inconsistent with other puzzles (a 3x3x3 with a U2 D2 applied to it is a DNF). I don't have a suggestion for how to fix this.

@SAuroux

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commented Dec 28, 2013

I don't think that the Regulations do clearly say that (6,6) is one move,
but yes, this should definitely be clarified.

Proposal:

12c2+) When counting the moves in case of a misalignment at the end of a
solve, x and y have to be considered seperately. Example: (5,2) is
considered one move, (5,5) i´s considered two moves.

2013/12/28 Jeremy Fleischman notifications@github.com

Take a solved sq1. Apply the move (6, 6) to it. This puzzle is exactly 1
move away from solved, as per
https://www.worldcubeassociation.org/regulations/2014-draft/#12c. By
https://www.worldcubeassociation.org/regulations/2014-draft/#10e3, that
means that this puzzle is solved with a 2 second penalty.

I asked Lucas about this, and he confirmed that this is a correct
interpretation of the regs, but not intended, as it is inconsistent with
other puzzles (a 3x3x3 with a U2 D2 applied to it is a DNF). I don't have a
suggestion for how to fix this.


Reply to this email directly or view it on GitHubhttps://github.com//issues/130
.

@jfly

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commented Dec 28, 2013

Your proposal sounds pretty good to me. Do you think it should also
explicitly mention that this metric is used for considering alignment
penalties, but not for scramble filtering?

I'm going to look into changing tnoodle's turn metric to count (2, 1) as 2
turns. Would the WRC be ok with changing their sq1 move metric to that?
On Dec 28, 2013 4:59 AM, "SAuroux" notifications@github.com wrote:

I don't think that the Regulations do clearly say that (6,6) is one move,
but yes, this should definitely be clarified.

Proposal:

12c2+) When counting the moves in case of a misalignment at the end of a
solve, x and y have to be considered seperately. Example: (5,2) is
considered one move, (5,5) i´s considered two moves.

2013/12/28 Jeremy Fleischman notifications@github.com

Take a solved sq1. Apply the move (6, 6) to it. This puzzle is exactly 1
move away from solved, as per
https://www.worldcubeassociation.org/regulations/2014-draft/#12c. By
https://www.worldcubeassociation.org/regulations/2014-draft/#10e3, that
means that this puzzle is solved with a 2 second penalty.

I asked Lucas about this, and he confirmed that this is a correct
interpretation of the regs, but not intended, as it is inconsistent with
other puzzles (a 3x3x3 with a U2 D2 applied to it is a DNF). I don't
have a
suggestion for how to fix this.


Reply to this email directly or view it on GitHub<
https://github.com/cubing/wca-documents/issues/130>
.


Reply to this email directly or view it on GitHubhttps://github.com//issues/130#issuecomment-31296151
.

@Claster

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commented Dec 28, 2013

(5,2) is considered one move

Why (5,2) is 1 move?

@SAuroux

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commented Dec 28, 2013

you are right, I suck. should be (5,1).

2013/12/29 Oleg Gritsenko notifications@github.com

(5,2) is considered one move
Why (5,2) is 1 move?


Reply to this email directly or view it on GitHubhttps://github.com//issues/130#issuecomment-31306860
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@lgarron

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commented Dec 30, 2013

I have the silly worry worry here is that we might set a definition of "move" that defines a Markov model whose steady-state distribution is not the one we use for selecting a random position.

Silly, but I worry about these things if I want to formalize them later. :-P

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