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version 1.0.0 cummean() function is providing weird results #5287

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nsingh-phd opened this issue May 31, 2020 · 2 comments
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version 1.0.0 cummean() function is providing weird results #5287

nsingh-phd opened this issue May 31, 2020 · 2 comments
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bug an unexpected problem or unintended behavior funs 😆 wip work in progress

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@nsingh-phd
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nsingh-phd commented May 31, 2020 •
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For testing, I have this small vector x where the long(er) way is giving me the results as expected version 1.0.0 cummean() is not.

library(tidyverse)
x <- 1:5

# long(er) way
cumsum(x) / seq_along(x)
#> [1] 1.0 1.5 2.0 2.5 3.0

# dplyr 0.8.5 cummean()
cummean(x)
#> [1] 1.0 1.5 2.0 2.5 3.0

# dplyr 1.0.0 cummean()
cummean(x)
#> [1] 1.000000 1.000000 1.333333 1.750000 2.200000

Created on 2020-05-31 by the reprex package (v0.3.0)
@brianrice2
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It looks like the indexing is off by one for dplyr_cummean in /src/funs.cpp, causing the first index to be repeated twice (and the last index to be dropped). I'll submit a pull request with a slight change which I think makes it work as intended.

@nsingh-phd
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nsingh-phd commented Jun 1, 2020 •
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Thanks @brianrice2 for requesting a quick fix.

@hadley hadley added bug an unexpected problem or unintended behavior funs 😆 labels Jun 5, 2020
@hadley hadley mentioned this issue Jun 5, 2020
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@hadley hadley added the wip work in progress label Jun 5, 2020
romainfrancois added a commit that referenced this issue Jun 9, 2020
@brianrice2 @romainfrancois
Update indexing for dplyr_cummean (#5287) (#5288)
76f61d0 
* Update indexing for dplyr_cummean (#5287)

* Add unit test for cummean

Check that cummean is consistent with the alternate method of
cummean(x) = cumsum(x) / seq_along(x).

Make sure future changes don't break the relationship above.

See also: #5287

* Update unit test for cummean

Add inline comments with exact values we expect to see,
so in the future it is easier to compare expected vs actual results.

* Update unit test for cummean

Add another check that we get expected values, independent of
cumsum and seq_along (in case of other bugs). That is,
cummean(1:5) = [1, 1.5, 2, 2.5, 3].

* Not assuming there is at least one element, +test

* + NEWS

Co-authored-by: Romain Francois <romain@rstudio.com>
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@hadley @romainfrancois @nsingh-phd @brianrice2