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@bradzacher @armano2
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Prefer using concise optional chain expressions instead of chained logical ands (prefer-optional-chain)

TypeScript 3.7 added support for the optional chain operator. This operator allows you to safely access properties and methods on objects when they are potentially null or undefined.

type T = {
  a?: {
    b?: {
      c: string;
      method?: () => void;
    };
  };
};

function myFunc(foo: T | null) {
  return foo?.a?.b?.c;
}
// is roughly equivalent to
function myFunc(foo: T | null) {
  return foo && foo.a && foo.a.b && foo.a.b.c;
}

function myFunc(foo: T | null) {
  return foo?.['a']?.b?.c;
}
// is roughly equivalent to
function myFunc(foo: T | null) {
  return foo && foo['a'] && foo['a'].b && foo['a'].b.c;
}

function myFunc(foo: T | null) {
  return foo?.a?.b?.method?.();
}
// is roughly equivalent to
function myFunc(foo: T | null) {
  return foo && foo.a && foo.a.b && foo.a.b.method && foo.a.b.method();
}

Because the optional chain operator only chains when the property value is null or undefined, it is much safer than relying upon logical AND operator chaining &&; which chains on any truthy value.

Rule Details

This rule aims enforce the usage of the safer operator.

Examples of incorrect code for this rule:

foo && foo.a && foo.a.b && foo.a.b.c;
foo && foo['a'] && foo['a'].b && foo['a'].b.c;
foo && foo.a && foo.a.b && foo.a.b.method && foo.a.b.method();

// this rule also supports converting chained strict nullish checks:
foo &&
  foo.a != null &&
  foo.a.b !== null &&
  foo.a.b.c != undefined &&
  foo.a.b.c.d !== undefined &&
  foo.a.b.c.d.e;

Examples of correct code for this rule:

foo?.a?.b?.c;
foo?.['a']?.b?.c;
foo?.a?.b?.method?.();

foo?.a?.b?.c?.d?.e;

When Not To Use It

If you are not using TypeScript 3.7 (or greater), then you will not be able to use this rule, as the operator is not supported.

Further Reading

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