file.getBlobURL w/o callback

[tomasparks]

I have a function that calls BlobUrlFromUrl(),
in that function, I call file.getBlobURL() but, before I get a response the function has returned cause undefined errors in the string :(

var xml = '<xml><krpano><scene id="' + pano.id + '" title="' + pano.title + '" >' xml = xml + '<preview url="' + BlobUrlFromUrl(files.preview, rootUrl) + '" />' xml = xml + '<image>' xml = xml + '<left url="' + BlobUrlFromUrl(files.left, rootUrl) + '"/>' xml = xml + '<front url="' + BlobUrlFromUrl(files.front, rootUrl) + '"/>' xml = xml + '<right url="' + BlobUrlFromUrl(files.right, rootUrl) + '"/>' xml = xml + '<back url="' + BlobUrlFromUrl(files.back, rootUrl) + '"/>' xml = xml + '<up url="' + BlobUrlFromUrl(files.up, rootUrl) + '"/>' xml = xml + '<down url="' + BlobUrlFromUrl(files.down, rootUrl) + '"/>' xml = xml + '</image></scene></krpano>';

function BlobUrlFromUrl(url,rootUrl) { torrent.files.forEach(function (file) { if ((file.path) == (rootUrl+'/'+url)) { file.getBlobURL(function (err, bloburl) {if (err) return log(err.message);log('file.getBlobURL() '+bloburl);success: bloburl;}); // log('torrent.files(): '+ bloburl); } }) }

runtime: https://tomasparks.name/krpano-and-webtorrent/index.html
source code: https://github.com/tomasparks/krpano-and-webtorrent

[alxhotel]

You can only get the Blob URL after the file is fully downloaded.

Try using the event done:

torrent.on('done', function () {
  // Here
})

[jimmywarting]

please wrap your code with 3 backticket so it becomes readable

also, whatsup with ;success: bloburl;?

[tomasparks]

also, whatsup with ;success: bloburl;?

it was a failed experiment that I didn't clean up

[jimmywarting]

you don't have to wait for the done event to finish all files as getBlobURL can be called straight await. however the getBlobURL is async so you need to get the blob urls before creating the xml, the alternative is that you create the xml and insert the blob url afterwards

something like this (untested):

file.getBlobURL(function(err, url) {
  xml.queryElement('left').setAttribute('src', url)
})

[tomasparks]

thanks 😞