Provide a Class to easily connect to the active Workboook

[fzumstein]

Probably best to make wb = ActiveWorkbook() or wb = Workbook.active() as otherwise `wb = Workbook(r'path\to\file.xls') would have to have an additional Parameter which makes it clunky.

[fzumstein]

Can't seem to make this work if the Workbook is unsaved:

    @classmethod
    def active(cls):
        com_app = dynamic.Dispatch('Excel.Application')
        print com_app.Application.ActiveWorkbook.Name
        return cls(com_app.Application.ActiveWorkbook.Name)

[fzumstein]

Maybe it's still worth doing it for saved spreadsheets only. Still saves you from looking up the path, and copy/pasting it.

[fzumstein]

For unsaved Workbooks, one can do wb = Workbook('Book1') ...

[ankostis]

This code succeeds most of the time (:-) to get an active but unsaved workbook:

import xlwings as xw

def get_active_workbook():
    from win32com.client import dynamic

    com_app = dynamic.Dispatch('Excel.Application')
    com_wb = com_app.ActiveWorkbook
    wb = xw.Workbook(xl_workbook=com_wb)

    return wb

[fzumstein]

Oh great - yeah haven't looked at this since the implementation of xl_workbook. The only issue I've noticed so far is that it's always going against the first instance of Excel if you have various instances...

[fzumstein]

To solve the problem with various instances, there seems to be no other solution than this: http://stackoverflow.com/a/2877943/918626

import win32gui

windows = []
win32gui.EnumWindows(lambda hwnd, resultList: resultList.append(win32gui.GetWindowText(hwnd)),windows)
#enumerates all the windows open from the top down
[i for i in windows if "Microsoft Excel" in i].pop(0)
#this one is closest to the top

then using GetObject on the name and sticking that into a Workbook as xl_workbook arg should probably work.