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//
// TwoSumII.swift
// LeetCode.swift
//
// Created by 叶帆 on 2020/3/8.
// Copyright © 2020 Suzhou Coryphaei Information&Technology Co., Ltd. All rights reserved.
//
/**
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
Your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
=====
给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数。
函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2。
说明:
返回的下标值(index1 和 index2)不是从零开始的。
你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素。
示例:
输入: numbers = [2, 7, 11, 15], target = 9
输出: [1,2]
解释: 2 与 7 之和等于目标数 9 。因此 index1 = 1, index2 = 2 。
*/
import Foundation
class Solution {
func twoSum(_ numbers: [Int], _ target: Int) -> [Int] {
var i = 0
var j = numbers.count - 1
while i < j {
let sum = numbers[i] + numbers[j]
if sum == target {
return [i+1, j+1]
}
if sum < target {
i += 1
} else {
j -= 1
}
}
return []
}
}
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