Skip to content
Permalink
Branch: master
Find file Copy path
Find file Copy path
Fetching contributors…
Cannot retrieve contributors at this time
60 lines (42 sloc) 1.43 KB
//
// ReverseString.swift
// LeetCode.swift
//
// Created by 叶帆 on 2020/3/7.
// Copyright © 2020 Suzhou Coryphaei Information&Technology Co., Ltd. All rights reserved.
//
/**
Write a function that reverses a string. The input string is given as an array of characters char[].
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
You may assume all the characters consist of printable ascii characters.
Example 1:
Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:
Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]
=====
编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
 
示例 1:
输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
*/
import Foundation
class Solution {
func reverseString(_ s: inout [Character]) {
// 为了实现 reverse() 函数
var i = 0
var j = s.count - 1
while i < j {
s.swapAt(i, j)
i += 1
j -= 1
}
}
}
You can’t perform that action at this time.