Get filename (Python API)

[levinuss]

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• Question

Hi,
I am working with the barely documented youtube-dl Pyhton API. What I want to do is get the final name of the file also using the provided outtmpl option. My code looks like this:

...
def get_title(url, template):
        ytdl_opts = {
            'simulate': 'True',
            'forcefilename': 'True',
            'outtmpl': '{}'.format(template),
            'logger': MyLogger()   #Exists above 
        }
        with youtube_dl.YoutubeDL(ytdl_opts) as ytdl:
            result = ytdl.extract_info("{}".format(url))
            title = result.get("title", None)
            return title

As you possibly know the title field from extract_info does only return the raw title of the video, not the 'editied' version with outtmpl. The logger gets the filename because the forcefilename option is speciefied. But I want to return the filename. Is there a way to do this? For now I have solved it by executing the command-line youtube-dl form pyhton. A way to do it with the API would be very cool.
Thanks,
Levin

[dstftw]

ytdl.prepare_filename(result).

[Tointoin]

When I use ytdl.prepare_filename(result), I get the temporary filename.webm with the .webm format. Is it possible to get directly the filename with the right format extension ?

my code :

            ydl_opts = {
                'format': 'bestaudio',
                'outtmpl': unicode('/my/path/%(title)s-%(id)s.%(ext)s'),
                'postprocessors': [{'key':'FFmpegExtractAudio'}],
                'restrictfilenames':True,
                'forcefilename':True,
            } 

            with youtube_dl.YoutubeDL(ydl_opts) as ydl:
                info = ydl.extract_info(uri, download=True)
                filename = ydl.prepare_filename(info)