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latest youtube-dl is not working for downloading udemy videos from business account #16553
Comments
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You did not provide account credentials to youtube-dl. |
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i provided but i can't show credentials over here let me bring you the sample command which i am using. |
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even if credentials are not provided, it should be able to download login page and asked for credentials which was there in previous version. |
showing 403 error while hitting udemy url. see below errors.
PS D:\> youtube-dl --verbose https://businessAccount.udemy.com/getting-started-with-microsoft-azure/learn/v4/overview [debug] System config: [] [debug] User config: [] [debug] Custom config: [] [debug] Command-line args: ['--verbose', 'https://businessAccount.udemy.com/getting-started-with-microsoft-azure/learn/v4/overview'] [debug] Encodings: locale cp1252, fs utf-8, out utf-8, pref cp1252 [debug] youtube-dl version 2018.05.26 [debug] Python version 3.6.1 (CPython) - Windows-10-10.0.16299-SP0 [debug] exe versions: none [debug] Proxy map: {} [generic] overview: Requesting header WARNING: Could not send HEAD request to https://businessAccount.udemy.com/getting-started-with-microsoft-azure/learn/v4/overview: HTTP Error 403: Unauthorized [generic] overview: Downloading webpage ERROR: Unable to download webpage: HTTP Error 403: Unauthorized (caused by <HTTPError 403: 'Unauthorized'>); please report this issue on https://yt-dl.org/bug . Make sure you are using the latest version; see https://yt-dl.org/update on how to update. Be sure to call youtube-dl with the --verbose flag and include its complete output. File "c:\users\samar\anaconda3\lib\site-packages\youtube_dl\extractor\common.py", line 579, in _request_webpage return self._downloader.urlopen(url_or_request) File "c:\users\samar\anaconda3\lib\site-packages\youtube_dl\YoutubeDL.py", line 2211, in urlopen return self._opener.open(req, timeout=self._socket_timeout) File "c:\users\samar\anaconda3\lib\urllib\request.py", line 532, in open response = meth(req, response) File "c:\users\samar\anaconda3\lib\urllib\request.py", line 642, in http_response 'http', request, response, code, msg, hdrs) File "c:\users\samar\anaconda3\lib\urllib\request.py", line 570, in error return self._call_chain(*args) File "c:\users\samar\anaconda3\lib\urllib\request.py", line 504, in _call_chain result = func(*args) File "c:\users\samar\anaconda3\lib\urllib\request.py", line 650, in http_error_default raise HTTPError(req.full_url, code, msg, hdrs, fp)