Vimeo password protected videos error

[Seehank]

I did use both --video-password and --cookies method, non of them worked. However downloading unprotected Vimeo video works just fine. Here is dump:

$ youtube-dl -F https://vimeo.com/66499057 --cookies /Users/filip/Downloads/architekti.txt --verbose
[debug] System config: []
[debug] User config: []
[debug] Custom config: []
[debug] Command-line args: [u'-F', u'https://vimeo.com/66499057', u'--cookies', u'/Users/filip/Downloads/architekti.txt', u'--verbose']
[debug] Encodings: locale UTF-8, fs utf-8, out UTF-8, pref UTF-8
[debug] youtube-dl version 2019.11.28
[debug] Python version 2.7.16 (CPython) - Darwin-17.7.0-x86_64-i386-64bit
[debug] exe versions: none
[debug] Proxy map: {}
[vimeo] 66499057: Downloading webpage
ERROR: Unable to download webpage: HTTP Error 404: Not Found (caused by HTTPError()); please report this issue on https://yt-dl.org/bug . Make sure you are using the latest version; type  youtube-dl -U  to update. Be sure to call youtube-dl with the --verbose flag and include its complete output.
  File "/usr/local/bin/youtube-dl/youtube_dl/extractor/common.py", line 627, in _request_webpage
    return self._downloader.urlopen(url_or_request)
  File "/usr/local/bin/youtube-dl/youtube_dl/YoutubeDL.py", line 2237, in urlopen
    return self._opener.open(req, timeout=self._socket_timeout)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 435, in open
    response = meth(req, response)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 548, in http_response
    'http', request, response, code, msg, hdrs)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 473, in error
    return self._call_chain(*args)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 407, in _call_chain
    result = func(*args)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 556, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)