add # symbol to escape characters #147
3 participants
In recent zsh you may be able to use ${(b)parameter} for this:
% s='foo#bar'
% print -r - ${(b)s}
foo\#barReference: http://zsh.sourceforge.net/Doc/Release/Expansion.html#Parameter-Expansion-Flags
Added commit 5237203 to address this using the b param expansion flag. Thanks @danielshahaf for the heads up
@danielshahaf Do you know when the b param expansion flag was added to zsh?
@ericfreese: And how this is going to help? I'm using # in my command line as an alias for various commands: https://github.com/seletskiy/zsh-hash-aliases
@danielshahaf Do you know when the
bparam expansion flag was added to zsh?
Commit zsh-users/zsh@6269db8, first released in 5.1.1, workers/35067.
@danielshahaf Looking into it a bit more, it looks like it was actually first released in 5.0.8: https://github.com/zsh-users/zsh/blob/zsh-5.0.8/ChangeLog#L314-L319
@seletskiy This would help by escaping # characters. I believe the b flag should escape all chars here.
Unfortunately, I think we should try to support zsh versions below 5.0.8, so will probably revert the above commit and keep the escape function, adding a note that we may be able to use the b flag at some point in the future.
@seletskiy I'm also not seeing an issue to begin with here. # characters seem to work just fine for me with the code as-is (tested w/ versions 5.0.8 and 5.2).
% zsh -f
%% alias -g -- '#wc'='| wc -l'
%% source zsh-autosuggestions.zsh
%% cat zsh-autosuggestions.zsh #wc
429
%% cat zsh-autosuggestions.zsh # <== Suggestions work fine hereCan you explain more specifically the exact problem you're having? What version of zsh are you using?
Please, reopen. It is the issue, otherwise I haven't reported it.
λ ~ alias -g -- '#'='| grep'
λ ~ echo 1 # 1
1
λ ~ _zsh_autosuggest_strategy_match_prev_cmd:18: bad math expression: operator expected at `1 # 1'
#_zsh_autosuggest_strategy_match_prev_cmd:18: bad math expression: operator expected at `1 # 1'
#
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