How to get a regulator-fixed initializing in off-state

[jbr-ia]

I see the regulator-fixed can be set to initialize to on in the device-tree by adding: regulator-boot-on;

Is there also a possibility to force the regulator to start off?
If the IO-pins are initialized with ACTIVE_HIGH it works fine, but I have a regulator on a custom board with stm32wb55rg microcontroller which has the IO-pins as ACTIVE_LOW. The regulator is described in the device-tree as:

i2c_pwr: i2c-pwr-ctrl {
	compatible = "regulator-fixed";
	regulator-name = "i2c-pwr-ctrl";
	enable-gpios = <&gpiob 5 GPIO_ACTIVE_LOW>;
	off-on-delay-us = <100000>;
};

After initialisation, the physical pin is low (and therefore the physical regulator is active active). But the regulator-fixed in zephyr thinks it is disabled. In order to really disable it, I now enable and disable the regulator in the code. But I think I am missing some option in the device-tree to let the initialisation disable the regulator. I am using zephyr v3.7.0

[rcolatobe]

@jbr-ia For some reason it didn't link to this post, I have #89973 open that addresses this issue.