Solution for Bridge and Torch Problem

dynamic_programming/brige_torch_problem.py

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+person_pace = [1, 2, 5, 10, 12, 16]
+person_pace.sort()  # Sort the array for optimal pairing
+people = len(person_pace)
+
+# Base cases
+if people == 1:
+    print("Min Time to Cross is:", person_pace[0])
+elif people == 2:
+    print("Min Time to Cross is:", person_pace[1])
+else:
+    total_time = 0
+    while people > 3:
+        # Strategy 1: Send the two fastest first, then the fastest returns
+        option1 = person_pace[1] + person_pace[0] + person_pace[-1] + person_pace[1]
+        # Strategy 2: Send the two slowest, then the fastest returns
+        option2 = person_pace[-1] + person_pace[0] + person_pace[-2] + person_pace[0]
+
+        # Choose the minimum of the two strategies
+        total_time += min(option1, option2)
+
+        # Remove the two slowest people who have crossed
+        person_pace = person_pace[:-2]
+
+    # Handle the last 2 or 3 people
+    if len(person_pace) == 3:
+        total_time += person_pace[2] + person_pace[0] + person_pace[1]
+    elif len(person_pace) == 2:
+        total_time += person_pace[1]
+
+    print("Min Time to Cross is:", total_time)