Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
The cache is initialized with a positive capacity.
Follow up:
Could you do both operations in O(1) time complexity?
Example:
LRUCache cache = new LRUCache( 2 /* capacity */ );
cache.put(1, 1);
cache.put(2, 2);
cache.get(1); // returns 1
cache.put(3, 3); // evicts key 2
cache.get(2); // returns -1 (not found)
cache.put(4, 4); // evicts key 1
cache.get(1); // returns -1 (not found)
cache.get(3); // returns 3
cache.get(4); // returns 4
class Node {
constructor(key, value, prev = null, next = null) {
this.key = key;
this.value = value;
this.prev = prev;
this.next = next;
}
}
class DoublyLinkedList {
constructor() {
this.head = new Node(0, 0);
this.tail = new Node(0, 0);
this.head.next = this.tail;
this.tail.prev = this.head;
}
insertHead(node) {
node.next = this.head.next;
node.prev = this.head;
this.head.next.prev = node;
this.head.next = node;
}
remove(node) {
node.prev.next = node.next;
node.next.prev = node.prev;
}
removeLast() {
let node = this.tail.prev;
let key = node.key;
this.remove(node);
return key;
}
}
class LRUCache {
constructor(capacity) {
this.capacity = capacity;
this.list = new DoublyLinkedList();
this.cache = new Map();
}
get(key) {
if (!this.cache.has(key)) {
return -1;
}
let node = this.cache.get(key);
this.list.remove(node);
this.list.insertHead(node);
return node.value;
}
put(key, value) {
let newNode = new Node(key, value);
if (this.cache.has(key)) {
this.list.remove(this.cache.get(key));
} else if (this.cache.size >= this.capacity) {
let leastUsedKey = this.list.removeLast();
this.cache.delete(leastUsedKey);
}
this.list.insertHead(newNode);
this.cache.set(key, newNode);
}
}