-
Notifications
You must be signed in to change notification settings - Fork 31
/
Copy path348. Design Tic-Tac-Toe.c
140 lines (116 loc) · 3.32 KB
/
348. Design Tic-Tac-Toe.c
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
/*
348. Design Tic-Tac-Toe
Design a Tic-tac-toe game that is played between two players on a n x n grid.
You may assume the following rules:
A move is guaranteed to be valid and is placed on an empty block.
Once a winning condition is reached, no more moves is allowed.
A player who succeeds in placing n of their marks in a horizontal, vertical, or diagonal row wins the game.
Example:
Given n = 3, assume that player 1 is "X" and player 2 is "O" in the board.
TicTacToe toe = new TicTacToe(3);
toe.move(0, 0, 1); -> Returns 0 (no one wins)
|X| | |
| | | | // Player 1 makes a move at (0, 0).
| | | |
toe.move(0, 2, 2); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 2 makes a move at (0, 2).
| | | |
toe.move(2, 2, 1); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 1 makes a move at (2, 2).
| | |X|
toe.move(1, 1, 2); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 2 makes a move at (1, 1).
| | |X|
toe.move(2, 0, 1); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 1 makes a move at (2, 0).
|X| |X|
toe.move(1, 0, 2); -> Returns 0 (no one wins)
|X| |O|
|O|O| | // Player 2 makes a move at (1, 0).
|X| |X|
toe.move(2, 1, 1); -> Returns 1 (player 1 wins)
|X| |O|
|O|O| | // Player 1 makes a move at (2, 1).
|X|X|X|
Follow up:
Could you do better than O(n2) per move() operation?
*/
typedef struct {
int *buff;
int *rn[2];
int *cn[2];
int *grid;
int n;
} TicTacToe;
#define IDX(R, C) ((R) * obj->n + (C))
/** Initialize your data structure here. */
TicTacToe* ticTacToeCreate(int n) {
TicTacToe *obj = calloc(1, sizeof(TicTacToe));
//assert(obj);
obj->n = n;
obj->buff = calloc((4 + n) * n, sizeof(int));
//assert(buff);
obj->rn[0] = &obj->buff[0 * n];
obj->rn[1] = &obj->buff[1 * n];
obj->cn[0] = &obj->buff[2 * n];
obj->cn[1] = &obj->buff[3 * n];
obj->grid = &obj->buff[4 * n];
return obj;
}
/** Player {player} makes a move at ({row}, {col}).
@param row The row of the board.
@param col The column of the board.
@param player The player, can be either 1 or 2.
@return The current winning condition, can be either:
0: No one wins.
1: Player 1 wins.
2: Player 2 wins. */
int ticTacToeMove(TicTacToe* obj, int row, int col, int player) {
int i;
obj->rn[player - 1][row] ++;
obj->cn[player - 1][col] ++;
if (obj->rn[player - 1][row] == obj->n ||
obj->cn[player - 1][col] == obj->n) {
return player;
}
obj->grid[IDX(row, col)] = player;
for (i = 0; i < obj->n && obj->grid[IDX(i, i)] == player; i ++) {
}
if (i == obj->n) return player;
for (i = 0; i < obj->n && obj->grid[IDX(i, obj->n - 1 - i)] == player; i ++) {
}
if (i == obj->n) return player;
return 0;
}
void ticTacToeFree(TicTacToe* obj) {
free(obj->buff);
free(obj);
}
/**
* Your TicTacToe struct will be instantiated and called as such:
* struct TicTacToe* obj = ticTacToeCreate(n);
* int param_1 = ticTacToeMove(obj, row, col, player);
* ticTacToeFree(obj);
*/
/*
Difficulty:Medium
Total Accepted:14.5K
Total Submissions:31.6K
Companies Microsoft Google
Related Topics Design
*/