arrayPairSum.py

# _*_ coding = utf-8 _*_
'''
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:
Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).
Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].
'''
"""
        :type nums: List[int]
        :rtype: int
        """
class Solution(object):
    def arrayPairSum(self, nums):
        nums.sort()
        n = len(nums)/2
        i , sumMax = 0 , 0
        while i < len(nums):
            sumMax += nums[i]
            i += 2
        return sumMax

if __name__ == "__main__":
	sol = Solution()
	nums = [5,1,3,2,-2,4]
	print(sol.arrayPairSum(nums))