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Copy pathstrict_evaluation.cpp
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strict_evaluation.cpp
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#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
struct segtree {
using ll = long long;
ll st[N << 2], lazy1[N << 2], lazy2[N << 2];
int tot1 = 0, tot2 = 0;
#define lc (rt << 1)
#define rc (rt << 1 | 1)
void push_up(int rt) {
st[rt] = min(st[lc], st[rc]);
}
void push_down(int rt) {
if(lazy2[rt]) {
lazy1[lc] = lazy1[rc] = 0;
lazy2[lc] = lazy2[rc] = lazy2[rt];
st[lc] = st[rc] = lazy2[rt];
}
if(lazy1[rt]) {
lazy1[lc] += lazy1[rt];
lazy1[rc] += lazy1[rt];
st[lc] += lazy1[rt];
st[rc] += lazy1[rt];
}
lazy1[rt] = lazy2[rt] = 0;
}
void build(int rt, int l, int r) {
if(l == r) {
cin>>st[rt];
return;
}
int mid = (l + r) >> 1;
build(lc, l, mid);
build(rc, mid + 1, r);
push_up(rt);
}
void update1(int rt, int l, int r, int x, int y, int val) {
if(l == x && y == r) {
st[rt] += val;
lazy1[rt] += val;
return;
}
int mid = (l + r) >> 1;
push_down(rt);
if(y <= mid) update1(lc, l, mid, x, y, val);
else if(x > mid) update1(rc, mid + 1, r, x, y, val);
else update1(lc, l, mid, x, mid, val), update1(rc, mid + 1, r, mid + 1, y, val);
push_up(rt);
}
void update2(int rt, int l, int r, int x, int y, int val) {
if(l == x && y == r) {
st[rt] = val;
lazy2[rt] = val;
lazy1[rt] = 0;
return;
}
int mid = (l + r) >> 1;
push_down(rt);
if(y <= mid) update2(lc, l, mid, x, y, val);
else if(x > mid) update2(rc, mid + 1, r, x, y, val);
else update2(lc, l, mid, x, mid, val), update2(rc, mid + 1, r, mid + 1, y, val);
push_up(rt);
}
ll query(int rt, int l, int r, int x, int y) {
if(x == l && y == r) return st[rt];
int mid = (l + r) >> 1;
push_down(rt);
if(y <= mid) return query(lc, l, mid, x, y);
else if(x > mid) return query(rc, mid + 1, r, x, y);
else return min(query(lc, l, mid, x, mid), query(rc, mid + 1, r, mid + 1, y));
}
} st;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int n, q;
cin>>n>>q;
st.build(1, 1, n);
while(q--) {
int opt, l, r, v;
cin>>opt;
switch(opt) {
case 1:
cin>>l>>r>>v;
st.update1(1, 1, n, l, r, v);
break;
case 2:
cin>>l>>r>>v;
st.update2(1, 1, n, l, r, v);
break;
case 3:
cin>>l>>r;
cout<<st.query(1, 1, n, l, r)<<'\n';
break;
}
}
return 0;
}