-
Notifications
You must be signed in to change notification settings - Fork 396
/
Copy pathmoveZeros.java
57 lines (45 loc) · 1.24 KB
/
moveZeros.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.
Example:
Input: [0,1,0,3,12]
Output: [1,3,12,0,0]
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.
Optimal time and space, but operations may be too many, EX: array with a lot of 0s
//TC: O(n) to go throguh all elements in the array
//SC: O(1)
class Solution {
public void moveZeroes(int[] nums) {
int index = 0;
for(int i=0; i<nums.length; i++)
{
if(nums[i]!=0)
{
nums[index] = nums[i];
index++;
}
}
for(int i=index; i<nums.length; i++)
{
nums[i] = 0;
}
}
}
MOST OPTIMAL SOLUTION
//TC: O(N)
class Solution {
public void moveZeroes(int[] nums) {
int lastNonZeroFoundAt = 0;
for(int i=0; i<nums.length; i++){
if(nums[i]!=0){
swap(lastNonZeroFoundAt, i, nums);
lastNonZeroFoundAt++;
}
}
}
public void swap(int i, int j, int[] nums){
int temp = nums[i];
nums[i]=nums[j];
nums[j]=temp;
}
}