forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy path_348.java
70 lines (61 loc) · 2.37 KB
/
_348.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
package com.fishercoder.solutions;
public class _348 {
public static class Solution1 {
/**
* credit: https://discuss.leetcode.com/topic/44548/java-o-1-solution-easy-to-understand
* <p>
* Key: in order to win a TicTacToe, you must have the entire row or column, thus, we don't need
* to keep track of the entire n^2 board. We only need to keep a count for each row and column.
* If at any time, a row or column matches the size of the board, then that player has won.
*/
public static class TicTacToe {
private int diagonal;
/**
* This is diagonal: |X| | | | |X| | | | |X| So, its condition is always like this: if (row ==
* col)
*/
private int antidiagonal;
/**
* This is antidiagonal: | | |X| | |X| | |X| | | So, its condition is always like this: if
* (col == size - row - 1)
*/
private int[] rows;
private int[] cols;
/**
* Initialize your data structure here.
*/
public TicTacToe(int n) {
rows = new int[n];
cols = new int[n];
}
/**
* Player {player} makes a move at ({row}, {col}).
*
* @param row The row of the board.
* @param col The column of the board.
* @param player The player, can be either 1 or 2.
* @return The current winning condition, can be either: 0: No one wins. 1: Player 1 wins. 2:
* Player 2 wins.
*/
public int move(int row, int col, int player) {
int toAdd = player == 1 ? 1 : -1;
rows[row] += toAdd;
cols[col] += toAdd;
int size = rows.length;
if (row == col) {
diagonal += toAdd;
}
if (col == (size - row - 1)) {
antidiagonal += toAdd;
}
if (Math.abs(rows[row]) == size
|| Math.abs(cols[col]) == size
|| Math.abs(antidiagonal) == size
|| Math.abs(diagonal) == size) {
return player;
}
return 0;
}
}
}
}