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Update 문자열-다루기-기본&12918&.js #105

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merged 3 commits into from
Sep 30, 2022

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soulhn
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@soulhn soulhn commented Sep 24, 2022

새롭게 추가된 문제 풀이

1/ 문자열 다루기 기본 eff3998

기존 풀이에 추가한 풀이

관련 이슈

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@codeisneverodd codeisneverodd left a comment

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좋은 코드 잘 보았습니다!!
남긴 코멘트는 참고용으로만 보아주세요 😄

Comment on lines 56 to 57
.includes(NaN);
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NaN 이 있느냐를 확인하시는 것이라면, some 메서드를 사용해보셔도 좋을 것 같아요!

Suggested change
.map((i) => parseInt(i, 10))
.includes(NaN);
.some(i => isNaN(parseInt(i, 10)));

MDN some

Comment on lines 58 to 60
return false;
}
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@codeisneverodd codeisneverodd Sep 26, 2022

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early return 방식을 고려해보세요!
사용자(개발자)가 코드를 최소한으로 읽고 이해할 수 있도록, 함수 내에서 특정 조건에 return 이 되도록 되어있다면, 짧은 구문을 위로 올려 return 해보세요! depth 를 줄이고 가독성을 향상시킬 수 있습니다 😄

function solution(s) {
  if (s.length !== 4 && s.length !== 6) return false;
  
  return s.split('').some(i => isNaN(parseInt(i, 10)));
}

Early return pattern

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좋은 리뷰 감사합니다. 도움 많이 받아갑니다.

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function solution(s) {
if (s.length !== 4 && s.length !== 6) return false;

return !s.split('').some(i => isNaN(parseInt(i, 10)));
}
정답은 이렇게 되면 제출이 됩니다!

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@soulhn 혹시 수정하신 답으로 업로드 하고 싶으시다면, soulhn:soulhn-patch-1 브랜치로 새로운 내용을 push 하여 반영하여주세요!

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soulhn commented Sep 27, 2022

이렇게 올리는게 맞을까요 fork pr도 처음이였는데
변수가 발생해서 조금 어렵네요

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@soulhn 네!! 잘 올려주셨습니다 😄 머지합니다!

@codeisneverodd codeisneverodd merged commit 7b21a65 into codeisneverodd:main Sep 30, 2022
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2 participants