Designer PDF Viewer.java

/*When you select a contiguous block of text in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently. For example:

PDF-highighting.png

In this challenge, you will be given a list of letter heights in the alphabet and a string. Using the letter heights given, determine the area of the rectangle highlight in  assuming all letters are  wide.

For example, the highlighted . Assume the heights of the letters are  and . The tallest letter is  high and there are  letters. The hightlighted area will be  so the answer is .

Function Description

Complete the designerPdfViewer function in the editor below. It should return an integer representing the size of the highlighted area.

designerPdfViewer has the following parameter(s):

h: an array of integers representing the heights of each letter
word: a string
Input Format

The first line contains  space-separated integers describing the respective heights of each consecutive lowercase English letter, ascii[a-z].
The second line contains a single word, consisting of lowercase English alphabetic letters.

Constraints

, where  is an English lowercase letter.
 contains no more than  letters.
Output Format

Print a single integer denoting the area in  of highlighted rectangle when the given word is selected. Do not print units of measure.

Sample Input 0

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
abc
Sample Output 0

9
Explanation 0

We are highlighting the word abc:

Letter heights are ,  and . The tallest letter, b, is  high. The selection area for this word is .

Note: Recall that the width of each character is .

Sample Input 1

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 7
zaba
Sample Output 1

28
Explanation 1

The tallest letter in  is  at . The selection area for this word is .
*/
import java.util.*;

public class DO {
    public static void main(String args[])
    {Scanner sc=new Scanner(System.in);

    
     //inputing the string
        
        int arr[]=new int[26]; //aray for height of each alphabet
        
    
        int count=0;
        int brr[]=new int[10];
        char[] alpha= {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'}; //array containg alphabets from a-z

        
        
        for(int i=0;i<26;i++)
        {
            arr[i]=sc.nextInt(); //inputing length of each alphabet
        }
        String s=sc.next();
        for(int i=0;i<s.length();i++)
        {
            for(int j=0;j<26;j++)
            {
                if(s.charAt(i)==alpha[j])
                {
                    brr[count]=arr[j];
                    count++;
                }
            }
        }
    
        int big=0;
        for(int i=0;i<count;i++)
        {
            if(brr[i]>big)
            {
            big=brr[i];    
            }
        }
        System.out.println(big*(s.length()));
    }
}