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Copy path397 Integer Replacement.py
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397 Integer Replacement.py
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"""
Given a positive integer n and you can do operations as follow:
If n is even, replace n with n/2.
If n is odd, you can replace n with either n + 1 or n - 1.
What is the minimum number of replacements needed for n to become 1?
Example 1:
Input:
8
Output:
3
Explanation:
8 -> 4 -> 2 -> 1
Example 2:
Input:
7
Output:
4
Explanation:
7 -> 8 -> 4 -> 2 -> 1
or
7 -> 6 -> 3 -> 2 -> 1
Author: Rajeev Ranjan
"""
class Solution(object):
def integerReplacement(self, n):
"""
Simulation using dp fails since bi-directional
Simple recursion
Math solution: bit manipulation
https://discuss.leetcode.com/topic/58334/a-couple-of-java-solutions-with-explanations/
3 is a special case
:type n: int
:rtype: int
"""
ret = 0
while n != 1:
ret += 1
if n & 1 == 0:
n >>= 1
elif n == 0b11 or n >> 1 & 1 == 0:
n -= 1
else:
n += 1
return ret
def integerReplacementRecur(self, n):
"""
Simple recursion
:type n: int
:rtype: int
"""
if n == 1: return 0
ret = 1
if n%2 == 0:
ret += self.integerReplacement(n/2)
else:
ret += min(self.integerReplacement(n+1), self.integerReplacement(n-1))
return ret