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Copy path543 Diameter of Binary Tree.py
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543 Diameter of Binary Tree.py
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#!/usr/bin/python3
"""
Given a binary tree, you need to compute the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two
nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges
between them.
Author: Rajeev Ranjan
"""
# Definition for a binary tree node.
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution:
def __init__(self):
"""
dfs, return the longest path (#nodes) ended at the subroot/current node
"""
self.ret = 0
def diameterOfBinaryTree(self, root: TreeNode) -> int:
self.dfs(root)
return self.ret
def dfs(self, node):
"""
return #nodes ended at node including itself
"""
if not node:
return 0
l = self.dfs(node.left)
r = self.dfs(node.right)
self.ret = max(self.ret, l + 1 + r - 1) # path length is the #nodes - 1
return max(l, r) + 1