-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy path988 Smallest String Starting From Leaf.py
74 lines (58 loc) · 1.72 KB
/
988 Smallest String Starting From Leaf.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
#!/usr/bin/python3
"""
Given the root of a binary tree, each node has a value from 0 to 25 representing
the letters 'a' to 'z': a value of 0 represents 'a', a value of 1 represents
'b', and so on.
Find the lexicographically smallest string that starts at a leaf of this tree
and ends at the root.
(As a reminder, any shorter prefix of a string is lexicographically smaller: for
example, "ab" is lexicographically smaller than "aba". A leaf of a node is a
node that has no children.)
Example 1:
Input: [0,1,2,3,4,3,4]
Output: "dba"
Example 2:
Input: [25,1,3,1,3,0,2]
Output: "adz"
Example 3:
Input: [2,2,1,null,1,0,null,0]
Output: "abc"
Note:
The number of nodes in the given tree will be between 1 and 8500.
Each node in the tree will have a value between 0 and 25.
"""
# Definition for a binary tree node.
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
from typing import Tuple
from collections import deque
class Solution:
def __init__(self):
self.mn: Tuple[int] = None
def smallestFromLeaf(self, root: TreeNode) -> str:
"""
dfs
"""
self.dfs(root, deque())
if not self.mn:
return ""
return "".join(
chr(e + ord("a"))
for e in self.mn
)
def dfs(self, node, cur_deque):
if not node:
return
cur_deque.appendleft(node.val)
if not node.left and not node.right:
t = tuple(cur_deque)
if not self.mn or t < self.mn:
self.mn = t
else:
self.dfs(node.left, cur_deque)
self.dfs(node.right, cur_deque)
# need to pop at the end
cur_deque.popleft()