005-Solution.ipynb

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    "# 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.\n",
    "\n",
    "# What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?"
   ]
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    "_____\n",
    "\n",
    "## The prime numbers  between 1 and 20 are 1, 2, 3, 5, 7, 11, 13, 17, and 19\n",
    "\n",
    "## If a number is divisible by 20, then it is automatically also divisible by 1, 2, 4, 5, and 10\n",
    "\n",
    "## If a number is divisible by 18, then it is automatically also divisible by 3, 6, and 9\n",
    "\n",
    "## If a number is divisible by 16, then it is automatically also divisible by 8\n",
    "\n",
    "## If a number is divisible by 14, then it is automatically also divisible by 7\n",
    "\n",
    "\n",
    "## If a number is already divisible by 20 and 18, we know it's divisible by 12\n",
    "\n",
    "# Therefore, we know a number is divisible by all numbers from 1 to 20 if it's divisible by all of [11,13,14,16,17,18,19,20]"
   ]
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   "source": [
    "def check_divisible(x):\n",
    "    for num in [20,19,18,17,16,14,13,11]:\n",
    "        if x%num!=0:\n",
    "            return False\n",
    "    return True"
   ]
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    "i = 0\n",
    "\n",
    "x = False\n",
    "\n",
    "while x == False:\n",
    "    i+=1\n",
    "    x = check_divisible(i)"
   ]
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       "232792560"
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    "i"
   ]
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  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Answer = 232,792,560"
   ]
  }
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