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<h2><a href="https://leetcode.com/problems/minimum-operations-to-reduce-an-integer-to-0">2710. Minimum Operations to Reduce an Integer to 0</a></h2><h3>Medium</h3><hr><p>You are given a positive integer <code>n</code>, you can do the following operation <strong>any</strong> number of times:</p>
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<ul>
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<li>Add or subtract a <strong>power</strong> of <code>2</code> from <code>n</code>.</li>
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</ul>
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<p>Return <em>the <strong>minimum</strong> number of operations to make </em><code>n</code><em> equal to </em><code>0</code>.</p>
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<p>A number <code>x</code> is power of <code>2</code> if <code>x == 2<sup>i</sup></code>&nbsp;where <code>i &gt;= 0</code><em>.</em></p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> n = 39
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> We can do the following operations:
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- Add 2<sup>0</sup> = 1 to n, so now n = 40.
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- Subtract 2<sup>3</sup> = 8 from n, so now n = 32.
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- Subtract 2<sup>5</sup> = 32 from n, so now n = 0.
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It can be shown that 3 is the minimum number of operations we need to make n equal to 0.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> n = 54
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> We can do the following operations:
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- Add 2<sup>1</sup> = 2 to n, so now n = 56.
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- Add 2<sup>3</sup> = 8 to n, so now n = 64.
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- Subtract 2<sup>6</sup> = 64 from n, so now n = 0.
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So the minimum number of operations is 3.
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>
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</ul>

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