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2161-partition-array-according-to-given-pivot/README.md

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+<h2><a href="https://leetcode.com/problems/partition-array-according-to-given-pivot/">2161. Partition Array According to Given Pivot</a></h2><h3>Medium</h3><hr><p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>pivot</code>. Rearrange <code>nums</code> such that the following conditions are satisfied:</p>
+
+<ul>
+	<li>Every element less than <code>pivot</code> appears <strong>before</strong> every element greater than <code>pivot</code>.</li>
+	<li>Every element equal to <code>pivot</code> appears <strong>in between</strong> the elements less than and greater than <code>pivot</code>.</li>
+	<li>The <strong>relative order</strong> of the elements less than <code>pivot</code> and the elements greater than <code>pivot</code> is maintained.
+	<ul>
+		<li>More formally, consider every <code>p<sub>i</sub></code>, <code>p<sub>j</sub></code> where <code>p<sub>i</sub></code> is the new position of the <code>i<sup>th</sup></code> element and <code>p<sub>j</sub></code> is the new position of the <code>j<sup>th</sup></code> element. If <code>i &lt; j</code> and <strong>both</strong> elements are smaller (<em>or larger</em>) than <code>pivot</code>, then <code>p<sub>i</sub> &lt; p<sub>j</sub></code>.</li>
+	</ul>
+	</li>
+</ul>
+
+<p>Return <code>nums</code><em> after the rearrangement.</em></p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [9,12,5,10,14,3,10], pivot = 10
+<strong>Output:</strong> [9,5,3,10,10,12,14]
+<strong>Explanation:</strong> 
+The elements 9, 5, and 3 are less than the pivot so they are on the left side of the array.
+The elements 12 and 14 are greater than the pivot so they are on the right side of the array.
+The relative ordering of the elements less than and greater than pivot is also maintained. [9, 5, 3] and [12, 14] are the respective orderings.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [-3,4,3,2], pivot = 2
+<strong>Output:</strong> [-3,2,4,3]
+<strong>Explanation:</strong> 
+The element -3 is less than the pivot so it is on the left side of the array.
+The elements 4 and 3 are greater than the pivot so they are on the right side of the array.
+The relative ordering of the elements less than and greater than pivot is also maintained. [-3] and [4, 3] are the respective orderings.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
+	<li><code>-10<sup>6</sup> &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>
+	<li><code>pivot</code> equals to an element of <code>nums</code>.</li>
+</ul>