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Odd even LL
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/**
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* Given a singly linked list, group all odd nodes together followed by the even nodes.
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* Please note here we are talking about the node number and not the value in the nodes.
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*
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* You should try to do it in place.
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* The program should run in O(1) space complexity and O(nodes) time complexity.
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Example 1:
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Input: 1->2->3->4->5->NULL
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Output: 1->3->5->2->4->NULL
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Example 2:
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Input: 2->1->3->5->6->4->7->NULL
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Output: 2->3->6->7->1->5->4->NULL
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Note:
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The relative order inside both the even and odd groups should remain as it was in the input.
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The first node is considered odd, the second node even and so on ...
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*/
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/**
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* Definition for singly-linked list.
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* function ListNode(val) {
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* this.val = val;
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* this.next = null;
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* }
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*/
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/**
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* @param {ListNode} head
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* @return {ListNode}
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*/
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const oddEvenLinkedList = head => {
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if (!head) {
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return null;
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}
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let odd = head;
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let even = head.next;
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let evenHead = even;
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while (even !== null && even.next !== null) {
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odd.next = even.next;
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odd = odd.next;
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even.next = odd.next;
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even = even.next;
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}
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odd.next = evenHead;
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return head;
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}

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