Added solution

Author: avidLearnerInProgress

amazon/strong_password.py

@@ -0,0 +1,64 @@
+#!/bin/python3
+
+import math
+import os
+import random
+import re
+import sys
+
+
+'''
+It contains at least one special character. The special characters are: !@#$%^&*()-+ 
+'''
+
+# Complete the minimumNumber function below.
+def minimumNumber(n, password):
+    # Return the minimum number of characters to make the password strong
+    numbers = "0123456789"
+    lower_case = "abcdefghijklmnopqrstuvwxyz"
+    upper_case = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
+    special_characters = "!@#$%^&*()-+"
+
+    def checkNumbers(pwd):
+        if not pwd: return 0
+        return any(char.isdigit() for char in pwd)
+        return 0
+    
+    def checkLower(pwd):
+        if not pwd: return 0
+        return any(char.islower() for char in pwd)
+        return 0
+    
+    def checkUpper(pwd):
+        if not pwd: return 0
+        return any(char.isupper() for char in pwd)
+        return 0
+
+    def checkSpecial(pwd):
+        if not pwd: return 0
+        return any(char in special_characters for char in pwd)
+        return 0
+    
+    count = 0
+    if not checkSpecial(password):
+        count += 1
+    if not checkLower(password):
+        count += 1
+    if not checkUpper(password): 
+        count +=1
+    if not checkNumbers(password):
+        count += 1
+    return max(count, 6 - n)
+
+if __name__ == '__main__':
+    fptr = open(os.environ['OUTPUT_PATH'], 'w')
+
+    n = int(input())
+
+    password = input()
+
+    answer = minimumNumber(n, password)
+
+    fptr.write(str(answer) + '\n')
+
+    fptr.close()