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2070-most-beautiful-item-for-each-query.rb
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# frozen_string_literal: true
# 2070. Most Beautiful Item for Each Query
# Medium
# https://leetcode.com/problems/most-beautiful-item-for-each-query
=begin
You are given a 2D integer array items where items[i] = [pricei, beautyi] denotes the price and beauty of an item respectively.
You are also given a 0-indexed integer array queries. For each queries[j], you want to determine the maximum beauty of an item whose price is less than or equal to queries[j]. If no such item exists, then the answer to this query is 0.
Return an array answer of the same length as queries where answer[j] is the answer to the jth query.
Example 1:
Input: items = [[1,2],[3,2],[2,4],[5,6],[3,5]], queries = [1,2,3,4,5,6]
Output: [2,4,5,5,6,6]
Explanation:
- For queries[0]=1, [1,2] is the only item which has price <= 1. Hence, the answer for this query is 2.
- For queries[1]=2, the items which can be considered are [1,2] and [2,4].
The maximum beauty among them is 4.
- For queries[2]=3 and queries[3]=4, the items which can be considered are [1,2], [3,2], [2,4], and [3,5].
The maximum beauty among them is 5.
- For queries[4]=5 and queries[5]=6, all items can be considered.
Hence, the answer for them is the maximum beauty of all items, i.e., 6.
Example 2:
Input: items = [[1,2],[1,2],[1,3],[1,4]], queries = [1]
Output: [4]
Explanation:
The price of every item is equal to 1, so we choose the item with the maximum beauty 4.
Note that multiple items can have the same price and/or beauty.
Example 3:
Input: items = [[10,1000]], queries = [5]
Output: [0]
Explanation:
No item has a price less than or equal to 5, so no item can be chosen.
Hence, the answer to the query is 0.
Constraints:
* 1 <= items.length, queries.length <= 105
* items[i].length == 2
* 1 <= pricei, beautyi, queries[j] <= 109
=end
# @param {Integer[][]} items
# @param {Integer[]} queries
# @return {Integer[]}
def maximum_beauty(items, queries)
items.sort_by!(&:last)
queries.collect { |q| items.reverse_each.inject(nil) { |res, (p, b)| break b if p <= q } || 0 }
end
# **************** #
# TEST #
# **************** #
require "test/unit"
class Test_maximum_beauty < Test::Unit::TestCase
def test_
assert_equal [2, 4, 5, 5, 6, 6], maximum_beauty([[1, 2], [3, 2], [2, 4], [5, 6], [3, 5]], [1, 2, 3, 4, 5, 6])
assert_equal [4], maximum_beauty([[1, 2], [1, 2], [1, 3], [1, 4]], [1])
assert_equal [0], maximum_beauty([[10, 1000]], [5])
end
end