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+ //5
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+ //5 4 3 2 1 0 1 2 3 4 5
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+ // 4 3 2 1 0 1 2 3 4
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+ // 3 2 1 0 1 2 3
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+ // 2 1 0 1 2
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+ // 1 0 1
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+ // 0
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+ // 1 0 1
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+ // 2 1 0 1 2
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+ // 3 2 1 0 1 2 3
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+ // 4 3 2 1 0 1 2 3 4
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+ //5 4 3 2 1 0 1 2 3 4 5
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+
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+ import java .util .Scanner ;
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+
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+ public class PatternHourGlass {
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+
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+ public static void main (String [] args ) {
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+ Scanner sc = new Scanner (System .in );
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+ int n = 0 ;
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+ if (sc .hasNext ()) {
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+ n = sc .nextInt ();
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+ }
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+ int nr =2 *n +1 ;
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+ int nst =nr ;
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+ int nsp =0 ;
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+ int row =1 ;
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+ int val ;
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+ while (row <=nr ) {
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+ if (row <=nr /2 +1 ) {
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+ val =n -row +1 ;
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+ }else {
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+ val =row -nr /2 -1 ;
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+ }
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+ for (int csp = 1 ; csp <=nsp ;csp ++) {
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+ System .out .print (" " );
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+ }
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+ for (int cst = 1 ; cst <=nst ;cst ++) {
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+ if (cst <nst /2 +1 ) {
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+ System .out .print (val --+" " );
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+ }else if (cst ==nst /2 +1 ){
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+ System .out .print (val +" " );
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+ }else {
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+ System .out .print (++val +" " );
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+ }
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+ }
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+ System .out .println ();
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+ if (row <=nr /2 ) {
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+ nsp +=2 ;
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+ nst -=2 ;
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+ }else {
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+ nsp -=2 ;
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+ nst +=2 ;
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+ }
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+ row ++;
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+
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+ }
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+ }
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+
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+ }
Original file line number Diff line number Diff line change
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+ Take N as input. For a value of N=5, we wish to draw the following pattern :
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+
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+ 5 4 3 2 1 0 1 2 3 4 5
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+ 4 3 2 1 0 1 2 3 4
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+ 3 2 1 0 1 2 3
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+ 2 1 0 1 2
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+ 1 0 1
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+ 0
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+ 1 0 1
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+ 2 1 0 1 2
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+ 3 2 1 0 1 2 3
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+ 4 3 2 1 0 1 2 3 4
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+ 5 4 3 2 1 0 1 2 3 4 5
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+ Input Format
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+ Take N as input.
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+
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+ Constraints
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+ N <= 20
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+
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+ Output Format
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+ Pattern should be printed with a space between every two values.
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+
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+ Sample Input
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+ 5
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+
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