code refactoring

Author: Ram swaroop

src/me/ramswaroop/bits/MultipleOf3.java

@@ -55,6 +55,6 @@ public static void main(String a[]) {
  *
  * If sum of digits in a number is multiple of 3 then number is multiple of
  * 3 e.g., for 612 sum of digits is 9 so it’s a multiple of 3. But this solution
- * is not efficient. You have to get all decimal digits one by one, add them and then check if sum is multiple of 3.
- *
+ * is not efficient. You have to get all decimal digits one by one, add them and 
+ * then check if sum is multiple of 3.
  */