SUBQUERY6.sql

SELECT incidents.*,
       sub.incidents AS incidents_that_day
  FROM tutorial.sf_crime_incidents_2014_01 incidents
  JOIN ( SELECT date,
          COUNT(incidnt_num) AS incidents
           FROM tutorial.sf_crime_incidents_2014_01
          GROUP BY 1
       ) sub
    ON incidents.date = sub.date
 ORDER BY sub.incidents DESC, time
 
 
 -- The following query ranks all of the results according to how many incidents were reported in a given day.