Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
For example: Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its depth = 3.
递归。求二叉树 root 节点左子树和右子树的深度,其中较大的深度加 1 即为二叉树的深度。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1;
}
}
递归。带上当前节点的深度。
class Solution {
public int maxDepth(TreeNode root) {
return maxDepth(root, 0);
}
public int maxDepth(TreeNode root, int depth) {
if (root == null) {
return depth;
}
return Math.max(maxDepth(root.left, depth + 1), maxDepth(root.right, depth + 1));
}
}