The count-and-say sequence is the sequence of integers with the first five terms as following:
1. 1
2. 11
3. 21
4. 1211
5. 111221
- 1 is read off as "one 1" or 11.
- 11 is read off as "two 1s" or 21.
- 21 is read off as "one 2, then one 1" or 1211.
- Given an integer n, generate the nth term of the count-and-say sequence.
Note: Each term of the sequence of integers will be represented as a string.
Example 1:
Input: 1
Output: "1"
Example 2:
Input: 4
Output: "1211"
這題使用迭代將此次結果累加起來,不用擔心會爆或超時。
- 字串
- Run Time: 27 ms
- 時間複雜度: O(n)
- 空間複雜度: O(1)
class Solution(object):
def countAndSay(self, n):
stringList="1"
if n == 1:
return "1"
for i in range(n-1):
count=1
newList=""
for j in range(len(stringList)-1):
if stringList[j]!=stringList[j+1]:
newList=newList+str(count)+stringList[j]
count=1
else:
count=count+1
newList=newList+str(count)+stringList[-1]
stringList=newList
return newList