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code/lc100.java
@@ -0,0 +1,25 @@
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+package code;
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+/*
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+ * 100. Same Tree
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+ * 题意:判断两棵树是否一样
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+ * 难度:Easy
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+ * 分类:
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+ * 思路:
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+ * Tips:
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+ */
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+public class lc100 {
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+ public class TreeNode {
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+ int val;
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+ TreeNode left;
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+ TreeNode right;
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+ TreeNode(int x) {
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+ val = x;
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+ }
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+ public boolean isSameTree(TreeNode p, TreeNode q) {
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+ if(p==null&&q==null) return true;
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+ if( (p==null&&q!=null)||(q==null&&p!=null) ) return false;
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+ if(p.val!=q.val) return false;
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+ return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
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+}
code/lc119.java
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+
+import java.util.ArrayList;
+import java.util.List;
+ * 119. Pascal's Triangle II
+ * 题意:和118一样,就是输出不一样
+ * 分类:Array
+ * 思路:记一下 ArrayList.set 方法,不用重新 new ArrayList
+public class lc119 {
+ public List<Integer> getRow(int rowIndex) {
+ ArrayList<Integer> res = new ArrayList<>();
+ res.add(0,1);
+ while(rowIndex-->0){
+ for (int i = 1; i < res.size()-1 ; i++) {
+ res.set(i, res.get(i)+res.get(i+1));
+ return res;
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code/lc14.java
@@ -9,10 +9,6 @@
import java.util.Arrays;
public class lc14 {
- public static void main(String[] args) {
-
- }
public static String longestCommonPrefix(String[] strs) { //不是最优的方法,多做了比较
if(strs.length==0)
return "";
code/lc17.java
@@ -5,6 +5,7 @@
* 17. Letter Combinations of a Phone Number
* 题意:手机键盘字母输入
* 难度:Medium
+ * 思路:思路记一下,每次放到vector中,遍历vector,加上所有的可能
* 分类:String, Backtracking
*/
public class lc17 {
code/lc19.java
@@ -4,7 +4,7 @@
* 题意:删除链表中倒数第n个节点
* 分类:Linked List, Two Pointers
- * 思路:快慢指针,快指针达到链表尾部时,满指针所在位置即为操作的节点
+ * 思路:快慢指针,快指针达到链表尾部时,慢指针所在位置即为操作的节点
* 注意:看清题意,是倒数第n个,且复杂度为n
public class lc19 {
code/lc2.java
@@ -9,9 +9,6 @@
* 注意考虑两个链表长度不一致的问题
public class lc2 {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
int sum = 0;
code/lc26.java
@@ -4,6 +4,7 @@
* 题意:移除数组中重复元素
* 难度:Easy
* 分类:Array, Two Pointers
+ * lc27
public class lc26 {
public static void main(String[] args) {
code/lc27.java
@@ -6,7 +6,7 @@
* 思路:两个指针,分别O(n),指向要交换的位置和和他交换的数
* 答案中直接遍历一遍数组,放到位置上就行了,i++
- * Tips:
+ * Tips:lc26
public class lc27 {
public int removeElement(int[] nums, int val) {
code/lc28.java
* 分类:Two Pointers, String
* Tips:注意判断子串为空的方法为needle.length()==0,不要用needle==""
+ * 最优的解法应该是O(N)的,类似KMP的思路,不过面试不会让写KMP的
public class lc28 {
code/lc29.java
@@ -5,7 +5,7 @@
* 分类:Math, Binary Search
* 思路:被除数减去除数,除数每次左移一位,也就是*2 来实现类似二分的思想
- * Tips:注意下用long类型,以及溢出的情况
+ * Tips:注意下用long类型,以及溢出的情况,注意符号
public class lc29 {
code/lc83.java
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+ * 83. Remove Duplicates from Sorted List
+ * 题意:移除重复值的节点,链表已排序
+public class lc83 {
+ public class ListNode {
+ ListNode next;
+ ListNode(int x) {
+ public ListNode deleteDuplicates(ListNode head) {
+ if(head==null) return head;
+ ListNode curr = head;
+ ListNode res = head;
+ while(curr!=null){
+ while( head!=null && head.val==curr.val) head = head.next;
+ curr.next = head;
+ curr = head;
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readme.md
@@ -101,6 +101,7 @@ LeetCode 指南
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| 120 [Java](./code/lc120.java)
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| 121 [Java](./code/lc121.java)
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| 122 [Java](./code/lc122.java)
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+| 123 [Java](./code/lc123.java)
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| 124 [Java](./code/lc124.java)
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| 125 [Java](./code/lc125.java)
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| 127 [Java](./code/lc127.java)
@@ -129,6 +130,7 @@ LeetCode 指南
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| 171 [Java](./code/lc171.java)
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| 172 [Java](./code/lc172.java)
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| 179 [Java](./code/lc179.java)
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+| 188 [Java](./code/lc188.java)
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| 189 [Java](./code/lc189.java)
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| 190 [Java](./code/lc190.java)
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| 191 [Java](./code/lc191.java)
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| 617 [Java](./code/lc617.java)
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| 621 [Java](./code/lc621.java)
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| 647 [Java](./code/lc647.java)
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+| 714 [Java](./code/lc714.java)
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| 746 [Java](./code/lc746.java)
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| 771 [Java](./code/lc771.java)
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| 877 [Java](./code/lc877.java)
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