fizzBuzz.java

/*
This is slightly more difficult version of the famous FizzBuzz problem which is sometimes given as a first problem for job interviews. Consider the series of numbers beginning at start and running up to but not including end, so for example start=1 and end=5 gives the series 1, 2, 3, 4. Return a new String[] array containing the string form of these numbers, except for multiples of 3, use "Fizz" instead of the number, for multiples of 5 use "Buzz", and for multiples of both 3 and 5 use "FizzBuzz". In Java, String.valueOf(xxx) will make the String form of an int or other type. This version is a little more complicated than the usual version since you have to allocate and index into an array instead of just printing, and we vary the start/end instead of just always doing 1..100.

fizzBuzz(1, 6) → ["1", "2", "Fizz", "4", "Buzz"]
fizzBuzz(1, 8) → ["1", "2", "Fizz", "4", "Buzz", "Fizz", "7"]
fizzBuzz(1, 11) → ["1", "2", "Fizz", "4", "Buzz", "Fizz", "7", "8", "Fizz", "Buzz"]
*/

public String[] fizzBuzz(int start, int end) {
  int l = end-start;
  String[] fb = new String[l];
  for(int i=start, j=0; i < end; i++,j++) {
    if( (i)%3 == 0 && (i)%5 == 0 ) {
      fb[j] = "FizzBuzz";
    }
    else if( (i)%3 == 0 ) {
      fb[j] = "Fizz";
    }
    else if ( (i)%5 == 0 ) {
      fb[j] = "Buzz";
    }
    else {
      fb[j] = String.valueOf(i);
    }
  }
  return fb;
}