title | type | tags | cover | dateModified | |
---|---|---|---|---|---|
List intersection |
snippet |
|
wooden-bowl |
2020-11-02 19:28:05 +0200 |
Returns a list of elements that exist in both lists.
- Create a
set
froma
andb
. - Use the built-in set operator
&
to only keep values contained in both sets, then transform theset
back into alist
.
def intersection(a, b):
_a, _b = set(a), set(b)
return list(_a & _b)
intersection([1, 2, 3], [4, 3, 2]) # [2, 3]