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| 1 | +/*https://leetcode.com/problems/minimum-path-sum/ |
| 2 | + * dp easy, striver op |
| 3 | + * |
| 4 | + */ |
| 5 | + |
| 6 | +private class Recursion { |
| 7 | + |
| 8 | + public int minPathSum(int[][] grid) { |
| 9 | + int n = grid.length; |
| 10 | + int m = grid[0].length; |
| 11 | + return recursion(n - 1, m - 1, grid); |
| 12 | + } |
| 13 | + |
| 14 | + private int recursion(int i, int j, int[][] grid) { |
| 15 | + if (i == 0 && j == 0) return grid[0][0]; |
| 16 | + if (i < 0 || j < 0) return Integer.MAX_VALUE; |
| 17 | + int up = recursion(i - 1, j, grid); // travelling from upside |
| 18 | + int left = recursion(i, j - 1, grid); // travelling from righside |
| 19 | + return grid[i][j] + Math.min(up, left); |
| 20 | + } |
| 21 | +} |
| 22 | + |
| 23 | +private class memoization { |
| 24 | + int dp[][]; |
| 25 | + |
| 26 | + public int minPathSum(int[][] grid) { |
| 27 | + int n = grid.length; |
| 28 | + int m = grid[0].length; |
| 29 | + dp = new int[n][m]; |
| 30 | + for (int a[] : dp) { |
| 31 | + Arrays.fill(a, -1); |
| 32 | + } |
| 33 | + return recursion(n - 1, m - 1, grid); |
| 34 | + } |
| 35 | + |
| 36 | + private int recursion(int i, int j, int[][] grid) { |
| 37 | + if (i == 0 && j == 0) return grid[0][0]; |
| 38 | + if (i < 0 || j < 0) return Integer.MAX_VALUE; |
| 39 | + if (dp[i][j] != -1) return dp[i][j]; |
| 40 | + int up = recursion(i - 1, j, grid); // travelling from upside |
| 41 | + int left = recursion(i, j - 1, grid); // travelling from righside |
| 42 | + return dp[i][j] = grid[i][j] + Math.min(up, left); |
| 43 | + } |
| 44 | +} |
| 45 | + |
| 46 | +private class tabulation { |
| 47 | + int dp[][]; |
| 48 | + |
| 49 | + public int minPathSum(int[][] grid) { |
| 50 | + int n = grid.length; |
| 51 | + int m = grid[0].length; |
| 52 | + dp = new int[n][m]; |
| 53 | + for (int a[] : dp) { |
| 54 | + Arrays.fill(a, -1); |
| 55 | + } |
| 56 | + for (int i = 0; i < n; i++) { |
| 57 | + for (int j = 0; j < m; j++) { |
| 58 | + if (i == 0 && j == 0) dp[i][j] = grid[i][j]; |
| 59 | + if (dp[i][j] != -1) continue; else if (i == 0 && j != 0) dp[i][j] = |
| 60 | + grid[i][j] + dp[i][j - 1]; else if (i != 0 && j == 0) dp[i][j] = |
| 61 | + grid[i][j] + dp[i - 1][j]; else { |
| 62 | + dp[i][j] = grid[i][j] + Math.min(dp[i - 1][j], dp[i][j - 1]); |
| 63 | + } |
| 64 | + } |
| 65 | + } |
| 66 | + |
| 67 | + return dp[n - 1][m - 1]; |
| 68 | + } |
| 69 | +} |
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