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| 1 | +//Hackerrank Problem - Circular Palindromes |
| 2 | +// Level - Hard |
| 3 | +#include <algorithm> |
| 4 | +#include <iostream> |
| 5 | +#include <cassert> |
| 6 | +#include <cstdlib> |
| 7 | +#include <cstring> |
| 8 | +#include <cstdio> |
| 9 | +#include <cmath> |
| 10 | +#include <queue> |
| 11 | +#include <map> |
| 12 | +#include <set> |
| 13 | + |
| 14 | +using namespace std; |
| 15 | + |
| 16 | +#define type(x) __typeof((x).begin()) |
| 17 | +#define foreach(i, x) for(type(x) i = (x).begin(); i != (x).end(); i++) |
| 18 | +#define hash ___hash |
| 19 | + |
| 20 | +typedef long long ll; |
| 21 | +typedef pair < int, int > ii; |
| 22 | + |
| 23 | +const int inf = 1e9 + 333; |
| 24 | +const ll linf = 1e18 + 333; |
| 25 | + |
| 26 | +const int N = 2e6 + 5; |
| 27 | + |
| 28 | +int n; |
| 29 | +char s[N]; |
| 30 | +bool h[N]; |
| 31 | +int go_odd[N], go_even[N], tmp[N << 1], rad[N << 1], ans[2][N]; |
| 32 | + |
| 33 | +void manacher() { |
| 34 | + memset(tmp, 0, sizeof(tmp)); |
| 35 | + memset(rad, 0, sizeof(rad)); |
| 36 | + int m = n * 2 + 1; |
| 37 | + for(int i = 0; i < m; i++) |
| 38 | + tmp[i] = '#'; |
| 39 | + for(int i = 0; i < n; i++) |
| 40 | + tmp[i * 2 + 1] = s[i + 1]; |
| 41 | + int i = 0, j = 0; |
| 42 | + while(i < m) { |
| 43 | + while(i - j >= 0 and i + j < m and tmp[i - j] == tmp[i + j]) |
| 44 | + j++; |
| 45 | + rad[i] = j; |
| 46 | + int k = 1; |
| 47 | + while(rad[i - k] < rad[i] - k) { |
| 48 | + rad[i + k] = rad[i - k]; |
| 49 | + k++; |
| 50 | + } |
| 51 | + i += k; |
| 52 | + j = max(0, j - k); |
| 53 | + } |
| 54 | + for(int i = 1; i <= n; i++) |
| 55 | + go_odd[i] = rad[(i - 1) * 2 + 1] / 2;//abcba --> go_odd[3] = 3 |
| 56 | + for(int i = 1; i <= n; i++) |
| 57 | + go_even[i - 1] = rad[(i - 1) * 2] / 2;//abccba --> go_even[3] = 3 |
| 58 | +} |
| 59 | + |
| 60 | +void solveOdd(bool w) { |
| 61 | + int oth = 0; |
| 62 | + set < ii > go; |
| 63 | + for(int i = 1; i <= (n + 1) / 2; i++) { |
| 64 | + go.insert({go_odd[i], i}); |
| 65 | + } |
| 66 | + for(int i = 1; i <= n; i++) { |
| 67 | + while(go.size()) { |
| 68 | + int x = go.rbegin() -> first; |
| 69 | + int id = go.rbegin() -> second; |
| 70 | + if(id < i) { |
| 71 | + go.erase(*go.rbegin()); |
| 72 | + continue; |
| 73 | + } |
| 74 | + int mx = (id - i + 1) * 2 - 1; |
| 75 | + if(x > mx) { |
| 76 | + oth = max(oth, id); |
| 77 | + go.erase(*go.rbegin()); |
| 78 | + continue; |
| 79 | + } |
| 80 | + break; |
| 81 | + } |
| 82 | + if(go.size()) |
| 83 | + ans[w][i] = max(ans[w][i], go.rbegin() -> first); |
| 84 | + if(oth >= i) |
| 85 | + ans[w][i] = max(ans[w][i], (oth - i + 1) * 2 - 1); |
| 86 | + //printf("ans[%d] = %d oth = %d\n", i, ans[w][i]); |
| 87 | + int add = (n + 1) / 2 + i; |
| 88 | + go.insert({go_odd[add], add}); |
| 89 | + } |
| 90 | +} |
| 91 | + |
| 92 | +int get(int x, int y) { |
| 93 | + y -= x - 1; |
| 94 | + return min(y, n - y) * 2; |
| 95 | +} |
| 96 | + |
| 97 | +void solveEven(bool w) { |
| 98 | + int oth = 0; |
| 99 | + set < ii > go; |
| 100 | + for(int i = 1; i <= (n + 1) / 2; i++) { |
| 101 | + go.insert({go_even[i], i}); |
| 102 | + } |
| 103 | + for(int i = 1; i <= n; i++) { |
| 104 | + while(go.size()) { |
| 105 | + int x = go.rbegin() -> first; |
| 106 | + int id = go.rbegin() -> second; |
| 107 | + if(id < i) { |
| 108 | + go.erase(*go.rbegin()); |
| 109 | + continue; |
| 110 | + } |
| 111 | + int mx = get(i, id); |
| 112 | + if(x > mx) { |
| 113 | + oth = max(oth, id); |
| 114 | + go.erase(*go.rbegin()); |
| 115 | + continue; |
| 116 | + } |
| 117 | + break; |
| 118 | + } |
| 119 | + if(go.size()) |
| 120 | + ans[w][i] = max(ans[w][i], go.rbegin() -> first); |
| 121 | + if(oth >= i) |
| 122 | + ans[w][i] = max(ans[w][i], get(i, oth)); |
| 123 | + //printf("ans[%d] = %d\n", i, ans[w][i]); |
| 124 | + int add = (n + 1) / 2 + i; |
| 125 | + go.insert({go_even[add], add}); |
| 126 | + } |
| 127 | +} |
| 128 | + |
| 129 | + |
| 130 | +int main () { |
| 131 | + |
| 132 | + scanf("%d %s", &n, s + 1); |
| 133 | + |
| 134 | + for(int i = 1; i <= n; i++) |
| 135 | + s[i + n] = s[i]; |
| 136 | + |
| 137 | + |
| 138 | + n *= 2; |
| 139 | + manacher(); |
| 140 | + n /= 2; |
| 141 | + |
| 142 | + for(int i = 1; i <= n + n; i++) { |
| 143 | + go_odd[i] *= 2; |
| 144 | + go_odd[i] -= 1; |
| 145 | + go_even[i] *= 2; |
| 146 | + } |
| 147 | + |
| 148 | + solveOdd(0); |
| 149 | + solveEven(0); |
| 150 | + |
| 151 | + |
| 152 | + |
| 153 | + reverse(s + 1, s + n * 2 + 1); |
| 154 | + |
| 155 | + n *= 2; |
| 156 | + manacher(); |
| 157 | + n /= 2; |
| 158 | + |
| 159 | + for(int i = 1; i <= n + n; i++) { |
| 160 | + go_odd[i] *= 2; |
| 161 | + go_odd[i] -= 1; |
| 162 | + go_even[i] *= 2; |
| 163 | + } |
| 164 | + |
| 165 | + solveOdd(1); |
| 166 | + solveEven(1); |
| 167 | + |
| 168 | + printf("%d\n", max(ans[0][1], ans[1][1])); |
| 169 | + |
| 170 | + for(int i = 2; i <= n; i++) { |
| 171 | + printf("%d\n", max(ans[0][i], ans[1][n + 2 - i])); |
| 172 | + } |
| 173 | + |
| 174 | + return 0; |
| 175 | + |
| 176 | +} |
| 177 | + |
| 178 | + |
| 179 | + |
| 180 | + |
| 181 | + |
| 182 | + |
| 183 | + |
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