Implement a magic directory with buildDict
, and search
methods.
For the method buildDict
, you'll be given a list of non-repetitive words to build a dictionary.
For the method search
, you'll be given a word, and judge whether if you modify exactly one character into anothercharacter in this word, the modified word is in the dictionary you just built.
Example 1:
Input: buildDict(["hello", "leetcode"]), Output: Null
Input: search("hello"), Output: False
Input: search("hhllo"), Output: True
Input: search("hell"), Output: False
Input: search("leetcoded"), Output: False
Note:
- You may assume that all the inputs are consist of lowercase letters
a-z
. - For contest purpose, the test data is rather small by now. You could think about highly efficient algorithm after the contest.
- Please remember to RESET your class variables declared in class MagicDictionary, as static/class variables are persisted across multiple test cases. Please see here for more details.
实现一个带有 buildDict, 以及 search 方法的魔法字典。对于 buildDict 方法,你将被给定一串不重复的单词来构建一个字典。对于 search 方法,你将被给定一个单词,并且判定能否只将这个单词中一个字母换成另一个字母,使得所形成的新单词存在于你构建的字典中。
- 实现
MagicDictionary
的数据结构,这个数据结构内会存储一个字符串数组,当执行Search
操作的时候要求判断传进来的字符串能否只改变一个字符(不能增加字符也不能删除字符)就能变成MagicDictionary
中存储的字符串,如果可以,就输出true
,如果不能,就输出false
。 - 这题的解题思路比较简单,用 Map 判断即可。