Long Pressed Name.

Author: recherst

Easy/925.Long Pressed Name.playground/Contents.swift

@@ -0,0 +1,72 @@
+/**
+ Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.
+
+ You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.
+
+  
+
+ Example 1:
+ Input: name = "alex", typed = "aaleex"
+ Output: true
+ Explanation: 'a' and 'e' in 'alex' were long pressed.
+ 
+ Example 2:
+ Input: name = "saeed", typed = "ssaaedd"
+ Output: false
+ Explanation: 'e' must have been pressed twice, but it was not in the typed output.
+  
+
+ Constraints:
+ - 1 <= name.length, typed.length <= 1000
+ - name and typed consist of only lowercase English letters.
+ */
+class Solution {
+    func isLongPressedName(_ name: String, _ typed: String) -> Bool {
+        var nameArr = [String(name.first!)]
+        for (i, c) in name.enumerated() {
+            if i > 0 {
+                var character = nameArr.last!.last
+                if character == c {
+                    var last = nameArr.popLast()!
+                    last.append(c)
+                    nameArr.append(last)
+                } else {
+                    nameArr.append(String(c))
+                }
+            }
+        }
+        
+        var typedArr = [String(typed.first!)]
+        for (i, c) in typed.enumerated() {
+            if i > 0 {
+                var character = typedArr.last!.last
+                if character == c {
+                    var last = typedArr.popLast()!
+                    last.append(c)
+                    typedArr.append(last)
+                } else {
+                    typedArr.append(String(c))
+                }
+            }
+        }
+        
+        if nameArr.count != typedArr.count {
+            return false
+        }
+        for (i, e) in nameArr.enumerated() {
+            let element = typedArr[i]
+            if e.first != element.first {
+                return false
+            } else {
+                if e.count > element.count {
+                    return false
+                }
+            }
+        }
+        return true
+    }
+}
+
+let s = Solution()
+let r = s.isLongPressedName("leelee", "lleeelee")
+print(r)

Easy/925.Long Pressed Name.playground/contents.xcplayground

@@ -0,0 +1,4 @@
+<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
+<playground version='5.0' target-platform='ios' buildActiveScheme='true' importAppTypes='true'>
+    <timeline fileName='timeline.xctimeline'/>
+</playground>

Easy/925.Long Pressed Name.playground/playground.xcworkspace/contents.xcworkspacedata

@@ -126,6 +126,7 @@
 122. [Binary Number with Alternating Bits](https://github.com/recherst/leetcode-algtorithm/blob/main/Easy/693.Binary%20Number%20with%20Alternating%20Bits.playground/Contents.swift)
 123. [Count Binary Substrings](https://github.com/recherst/leetcode-algtorithm/blob/main/Easy/696.Count%20Binary%20Substrings.playground/Contents.swift)
 124. [Degree of an Array](https://github.com/recherst/leetcode-algtorithm/blob/main/Easy/697.Degree%20of%20an%20Array.playground/Contents.swift)
+125. [Long Pressed Name](https://github.com/recherst/leetcode-algtorithm/blob/main/Easy/925.Long%20Pressed%20Name.playground/Contents.swift)
 
 #### Medium