Skip to content

License clarification #256

Open
Open
@capfei

Description

@capfei

I'm a little confused on what the license is supposed to be.

With version 2.1.0, MIT is listed as the license in setup.py but the license file states Zlib. Is the python package actually under MIT and the license file is wrong or is MIT incorrect and it should be Zlib?
htt
ps://pypi.org/project/sklearn-pandas/

I also noticed that sklearn-pandas states BSD-3-Claues on conda-forge. Is this correct?
https://anaconda.org/conda-forge/sklearn-pandas

Metadata

Metadata

Assignees

No one assigned

    Labels

    No labels
    No labels

    Type

    No type

    Projects

    No projects

    Milestone

    No milestone

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions