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Documentation
https://docs.python.org/3/reference/simple_stmts.html#grammar-token-python-grammar-target
According to the docs, the grammar for the with statement
allows:
with_stmt ::= "with" with_stmt_contents
with_stmt_contents ::= with_item
with_item ::= expression "as" target
target ::= identifier | "*" target
from my understanding that would allow a python syntax like this:
class Test:
def __enter__(self):
return (1, 2)
def __exit__(self, exc_type, exc_value, traceback):
pass
with Test() as *mambo:
print(mambo, type(mambo))
But for me with python version 3.12.8
I get a syntax error:
File "/home/gringo/accessia/main/controller_start/test.py", line 9
with Test() as *mambo:
^^^^^^
SyntaxError: starred assignment target must be in a list or tuple
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