Code review will not fail automatically in case of issues

[headless-kjh]

For some reason, there was an issue with the review
and action didn't cancel until the 6-hour timeout had elapsed

@@ -6,6 +6,7 @@
import lombok.Getter;

import java.math.BigDecimal;
import java.math.RoundingMode;

@Getter
@Builder(access = AccessLevel.PRIVATE)
@@ -21,6 +22,8 @@ public class SubscriptionPlanDto {
    public static SubscriptionPlanDto NONE() {
        // TODO: 구독 없는 경우 어떻게 처리? (플로우)
        return SubscriptionPlanDto.builder()
                .planCode("")
                .price(BigDecimal.ZERO)
                .name("이용중인 서비스 없음")
                .isActive(false)
                .build();
@@ -34,7 +37,7 @@ public static SubscriptionPlanDto of(SubscriptionPlan plan) {
                .description(plan.getDescription())
                .planCode(plan.getPlanCode())
                .price(plan.getPrice())
                .priceIncludeVat(plan.getPrice().multiply(BigDecimal.valueOf(1.1)))
                .priceIncludeVat(plan.getPrice().multiply(BigDecimal.valueOf(1.1)).setScale(0, RoundingMode.FLOOR)) // 1원단위 절삭
                .isActive(plan.getIsActive())
                .build();
    }

This code that tried, just simple

[anc95]

@headless-kjh Actually I have no idea what causes this. could you help to re-run the job, let's check if it doesn't exit for the PR every time

[headless-kjh]

I think the focus should be on the fact that the function does not terminate when a problem occurs, rather than on the cause of the problem itself.
No errors occurred during the "re-run".

[LukeSamkharadze]

OpenAI has really bad uptime, that could be the issue.

Are we sure this is being handled correctly?

https://status.openai.com

[headless-kjh]

We have the same error again today. It's not a special case. It seems that failure timeout or retry is necessary.