Name anything is defined for ruff but actually it's not.

[DantasB]

Let's suppose that we have the following code:

scripts.py

def get_google_info():
    return requests.get("https://google.com").status_code

if __name__ == '__main__':
    import requests
    print(get_google_info())

running ruff (version: 0.9.7) would return me no errors to that code (All checks passed! message).

But, this code will actually not execute, if it's used by someplace else with no requests reference. Ex:

main.py

from scripts import get_google_info

if __name__ == '__main__':
    print(get_google_info())

So, if i run:
scripts.py: output = 200
main.py: output = NameError: name 'requests' is not defined

Do you have any idea how could i use static check to avoid these errors?

[ntBre]

ruff is currently restricted to single-file analysis. Handling this example will require the multi-file analysis and type inference that we're working on in red-knot.